0=4.9x^2+12x-75

Solution for 0=4.9x^2+12x-75 equation:

0=4.9x^2+12x-75

We move all terms to the left:

0-(4.9x^2+12x-75)=0

We add all the numbers together, and all the variables

-(4.9x^2+12x-75)=0

We get rid of parentheses

-4.9x^2-12x+75=0

a = -4.9; b = -12; c = +75;
Δ = b2-4ac
Δ = -122-4·(-4.9)·75
Δ = 1614
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-\sqrt{1614}}{2*-4.9}=\frac{12-\sqrt{1614}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+\sqrt{1614}}{2*-4.9}=\frac{12+\sqrt{1614}}{-9.8}
$